Explanation:
Given:-
- The Values ( Attach by the User )
To find:-
Solution:- (Q.1)
![\sf \: Arithmetic \: mean = (Sum \: of \: all \: observation)/(No.of \: observations)\\\\\\: \implies \sf \: mean \: = (1 + 1 + 1 + 1 + 3 + 3 + 4 + 4 + 4 + 8 + 12)/(11)\\\\\\ : \implies \sf \: mean = (42)/(11) \\\\\\ : \implies \sf \: mean = 3.81](https://img.qammunity.org/2022/formulas/mathematics/college/4ozpffqeeiekzsshhb3q8tlf0im57y8n44.png)
Solution:- (Q.2)
![: \implies \sf \:median = \bigg({(n + 1)/(2) \bigg)^(th)}\\\\\\ :\implies \sf \:median = \bigg( {(11 + 1)/(2) \bigg)^(th)}\\\\\\: \implies \sf \:median = \bigg( (12)/(2) \bigg) ^(th)\\\\\\ : \implies \sf \:median = 6th \: item\\\\\\ : \implies \sf \:median = 3](https://img.qammunity.org/2022/formulas/mathematics/college/jzns6d62ts5lp4ra7tv4pvuu0kdm3fhaq4.png)
Solution:- (Q.3)
Mode = Number of Maximum times occurring in Observation.
Mode = 1 Because its Occurring most in the Observation.
Solution:- (Q.4):-
Range = Highest - Lowest
⠀⠀⠀⠀= ⠀⠀12 ⠀⠀- ⠀1
⠀⠀⠀⠀= ⠀⠀⠀⠀⠀11
.°. 11 is the Required Range