Question

The velocity of an object is +47 m/s at 3.0 seconds and is +65 m/s at 12.0 seconds. Calculate the acceleration of the object

Answer 1

`\boxed{\text{\sf \Large 2.0 m/s^2 $}}`

Step-by-step explanation:

Use acceleration formula

`\displaystyle \text{$ \sf acceleration=(change \ in\ velocity)/(change \ in \ time) $}`

`\displaystyle a=(65-47)/(12.0-3.0) =2.0`