Question

While on a scavenger hunt, a student walks 500 m north, 200 m east, 300 south and finally 400 m west What is the net displacement and direction of the student?​

Answer 1

~Pythagoras

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`d = √((500 - 300)^2 + (400 - 200)^2 )`

`d = \sqrt{200^(2) + 200 ^(2) }`

`d = √(40.000 * 2)`

`d = √(80.000)`

`d \approx 282,84 m`

Answer 2

282.84 m toward Northwest

Step-by-step explanation:

d = √(500-300)² + (400-200)²

=√(200²+200²)

= √(40000+40000)

= √ 80000

= 282.84 m

direction => Northwest