Answer:
The slope is 1 and your equation is y = x - 16
Explanation:
(6, -10) & (3, -13)
First you want to find the slope of the line that passes through these points. To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)
Plug in these values:
(-13 - (-10)) / (3 - 6)
Simplify the parentheses.
= (-13 + 10) / (-3)
= (-3) / (-3)
Simplify the fraction.
=-3/-3
= 1
This is your slope. Plug this value into the standard slope-intercept equation of y = mx + b.
y = 1x + b
or
y = x + b
To find b, we want to plug in a value that we know is on this line: in this case, I will use the second point (3, -13). Plug in the x and y values into the x and y of the standard equation.
-13 = 1(3) + b
To find b, multiply the slope and the input of x(3)
-13 = 3 + b
Now, subtract 3 from both sides to isolate b.
-16 = b
Plug this into your standard equation.
y = x - 16
This is your equation. From this we can see that the slope is 1.
Check this by plugging in the other point you have not checked yet (6, -10).
y = x - 16
-10 = (6) - 16
-10 = 6 - 16
-10 = -10
Your equation is correct.
Hope this helps!