99.5k views
15 votes
What is the slope of the line that passes through the points (6, -10)and (3, -13)?Write your answer in simplest form.

User Vynce
by
7.8k points

1 Answer

9 votes

Answer:

The slope is 1 and your equation is y = x - 16

Explanation:

(6, -10) & (3, -13)

First you want to find the slope of the line that passes through these points. To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(-13 - (-10)) / (3 - 6)

Simplify the parentheses.

= (-13 + 10) / (-3)

= (-3) / (-3)

Simplify the fraction.

=-3/-3

= 1

This is your slope. Plug this value into the standard slope-intercept equation of y = mx + b.

y = 1x + b

or

y = x + b

To find b, we want to plug in a value that we know is on this line: in this case, I will use the second point (3, -13). Plug in the x and y values into the x and y of the standard equation.

-13 = 1(3) + b

To find b, multiply the slope and the input of x(3)

-13 = 3 + b

Now, subtract 3 from both sides to isolate b.

-16 = b

Plug this into your standard equation.

y = x - 16

This is your equation. From this we can see that the slope is 1.

Check this by plugging in the other point you have not checked yet (6, -10).

y = x - 16

-10 = (6) - 16

-10 = 6 - 16

-10 = -10

Your equation is correct.

Hope this helps!

User Solub
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories