Question

Segment AB and segment CD intersect at point E. Segment AC and segment DB are parallel. If m∠A=41m∠A=41o and m∠D=56m∠D=56o, find the m∠AECm∠AEC.

Answer 1

m∠AEC = 83°

Explanation:

∠C and ∠D are alternate angles and are congruent because segment AC is parallel to DB

Therefore, m∠C = 56°

Sum of measures of angles of a triangle is 180.

So, m∠A + m∠C + m∠AEC = 180

41 + 56 + m∠AEC = 180

m∠AEC + 97 = 180

m∠AEC = 83°