Question

A 32.4 L gas sample at STP is compressed to a volume of 28.4 L, and the temperature is increased to 352 K.

What is the new pressure of the gas in atmospheres? Answer: 1.47atm

How do I solve this?

Answer 1

The new pressure of the gas is 1.47 atm.

Step-by-step explanation:

STP in chemistry is the abbreviation for standard temperature and pressure. In this case the standard temperature is 273 K (0 ° Celsius or 32 ° Fahrenheit) and the standard pressure is 1 atm of pressure.

The equation that relates P, V, and T is called the ideal gas “law”. This law relates the variables in an initial state 1 and a final state 2 by the expression:

`(P1*V1)/(T1) =(P2*V2)/(T2)`

In this case:

• P1= 1 atm
• V1= 32.4 L
• T1= 273 K
• P2= ?
• V2= 28.4 L
• T2= 352 K

Replacing:

`(1 atm*32.4 L)/(273 K) =(P2*28.4 L)/(352 K)`

and solving you get:

`P2=(352 K)/(28.4 L) (1 atm*32.4 L)/(273 K)`

P2= 1.47 atm

The new pressure of the gas is 1.47 atm.