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The ancient fish fossils were dated using C-14. If 1/16 the original amount of C-14 remains in the skeletons, approximately how old are the fish. The half-life of C-14 is 5730.

a) 11,460 years
b) 17,190 years
c) 22,920 years
d) 28,650 years​

User WalterF
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1 Answer

12 votes

Answer:

c) 22,920 years

Step-by-step explanation:

The half-life of C-14 is 5730 so in 5730 years , amount of C-14 is reduced to half.

In 5730 x 2 years , the amount of C-14 is reduced to 1/4 .

In 5730 x 3 years , the amount of C-14 is reduced to 1/8 .

In 5730 x 4 years , the amount of C-14 is reduced to 1/16 .

In 22920 years , the amount of C-14 is reduced to 1/16 .

So the answer is 22920 years.

User Xrd
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