Question

In ΔBCD, the measure of ∠D=90°, the measure of ∠C=83°, and DB= 1.3feet. What is the length of CD to the nearest tenth of a foot.

Answer 1

`CD\approx0.2`

Explanation:

By the tangent ratio,
`tanC=(DB)/(CD)`. Substituting the given values into this equation gives us:

`tan83`°
`= (1.3)/(CD)`

`CD*tan83`°
`=1.3` (Multiply both sides of the equation by
`CD`)

`CD=(1.3)/(tan83\textdegree)` (Divide both sides of the equation by
`tan83\textdegree`)

`CD=0.15962\approx0.2`

Hope this helps!