Question

A woman has a total of $9,000 to invest. She invests part of the money in an account that pays 7 % per year and

the rest in an account that pays 11 % per year. If the interest earned in the first year is $790, how much did she
invest in each account?

Answer 1

Hi! I believe this is your answer:

$750

Step by step explanation:

interest + interest = total interest

0.08*x + 0.09*(9000-x) = 750 dollars

0.08x + 810 - 0.09x = 750

-0.01x = 750 - 810 = -60 ====> x = %28-60%29%2F%28-0.01%29 = 6000.

Final answer:

$6000 was invested at 8%. The rest 9000-6000 = 3000 dollars were invested at 9%.

Check. 0.08*6000 + 0.09*3000 = 480 + 270 = 750 dollars.