Question

Factorize 2x^2-5/3xy-2y^2

Answer 1

`y = 0 \: .x = (2)/(3) y`

Step-by-step explanation:

`\frac{2 {x}^(2) - 5 }{3xy - 2 {y}^(2) }`

`3xy - 2 {y}^(2) = 0`

`y * (3x - 2y) = 0`

`y = 0 = 3x - 2y = 0`

`y = 0 = 3x = 2y`

`y = 0`

`x = (2)/(3) y`

`y = 0. \: x = (2)/(3) y`

Answer 2

I hope it helps you