Question

Which shows the equation below written in the form ax^2+bx+c=0. x+9=4(x-1)^2

Answer 1

`4x^2 - 9x - 5 = 0`

Explanation:

To place the equation in standard form, we expand the operations. So

`4(x-1)^2 = x + 9`

`4(x^2-2x+1) = x + 9`

`4x^2 - 8x + 4 - x - 9 = 0`

Combining the like terms:

`4x^2 - 9x - 5 = 0`