Question

Solutions to the quadratic equation x^2+3x-28=0

Answer 1

x = -7 ; x=4

Explanation:

The easiest way to solve this would be using the quadratic formula, so let's go ahead with that :)

`x=(-b\pm √(b^2-4ac))/(2a)\\x=(-3\pm √(3^2-4\cdot \:1\cdot \left(-28\right)))/(2\cdot 1)\\x=(-3\pm √(121) )/(2) \\\\x=(-3\pm 11)/(2) \\\\x=(-3-11)/(2) , x=(-3+11)/(2) \\x=-7, x=4`

Answer 2

look on the graph

Explanation:

the solutions are x = -7 and x=4