1 Answer

THeSiD · Answer 1 · 2022-04-19T17:11:08+0000

Answer:

$m\angle AED=90\degree$

$m\angle DAE=53\degree$

$m\angle BCE= 53\degree$

Explanation:

ABCD is a rhombus. AC and BD are its diagonals intersecting at point E.

Diagonals of a rhombus bisects at right angles.

$\therefore m\angle AED=90\degree$

$In\: \triangle AED$

$m\angle DAE=90\degree-m\angle EDA$

$m\angle DAE=90\degree-37\degree$

$m\angle DAE=53\degree$

$\because m\angle BCE= m\angle DAE$

(Alternate angles)

$\therefore m\angle BCE= 53\degree$

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