Question

Please help! Please don't answer if you don't know!​

Answer 1

[-0.25 1.25]

[ ]

[-0.75 2.75]

If not satisfied than..

You can write it in other way as show in step by step

Explanation:

Step 1:

First of all find the determinate.

Cross multiply the number 11 ✖ -1

1. detA = 11 × -1

= -11 ---eq1

And now cross multiply the number 3 ✖ - 5

1. detA = 3 × -5

= -15 ---eq2

Now we use eq 1 and 2

detA = (-11)-(-15)

Minus cancels minus

So it becomes

detA = -11 + 15

= 4

Step 2:

We find adjacent of the given.

[11 -5]

adjA= [ ]

[3 -1 ]

We change the places. The number 11 goes to in place of -1. -1 goes in place of 11.

And we change the signs of -5 and 3. -5 becomes 5 and 3 becomes -3.

We get

[-1 5]

adjA = [ ]

[-3 11]

Step 3:

Now we use the following formula

1

A^-1 = -------- adjA

detA

1 [-1 5]

A^-1 = ------- [ ]

4 [-3 11]

And now multiply

1

---- with each number of adjA.

4

And than subtract..

And you will get the inverse matrix

If the answer comes same than that's the answer for inverse matrix

Thank you.