Question

It’ll be a miracle if someone helps

Answer 1

Answer: ½

Explanation:

`{ \tt{ {d}^(2) - b }}`

• d is ¼
• b is -7/16

`\dashrightarrow \: { \tt{ {( (1)/(4) )}^(2) - ( - (7)/(16)) }} \\ \\ { \tt{ = (1)/(16) + (7)/(16) }} \\ \\ = { \tt{ ((1 + 7))/(16) }} \\ \\ = { \tt{ (8)/(16) }}`

» Reduce the denominator and numerator by dividing all by 8/8

`={ \tt{ (8)/(16) / (8)/(8) }} \\ \\ = { \tt{ (1)/(2) }}`

Answer 2

1/2

Explanation:

Put the values where the variables are and do the arithmetic.

`d^2-b=\left((1)/(4)\right)^2-\left(-(7)/(16)\right)=(1)/(16)+(7)/(16)\\\\=(1+7)/(16)=(8)/(16)=\boxed{(1)/(2)}`