Question

How much heat is released when 1.4 mol of hydrogen fluoride are produced?

H2(g) +F2(g) → 2HF(g) +536kJ

(Please show work, Thanks!)

Answer 1

+375.2 KJ.

Step-by-step explanation:

The balanced equation for the reaction is given below:

H₂ + F₂ —> 2HF ΔH = +536 KJ

From the balanced equation above,

2 moles of HF required +536 KJ .

Finally, we shall determine the heat required to produce 1.4 mol of hydrogen fluoride, HF. This is illustrated below:

From the balanced equation above,

2 moles of HF required +536 KJ .

Therefore, 1.4 moles of HF will require = (1.4 × 536)/2 = +375.2 KJ

Thus, +375.2 KJ of heat energy is required.