Question

If 42 grams of HCl reacts, what is the theoretical yield of hydrogen gas produced?

Answer 1

`m_(H_2)=1.2gH_2`

Step-by-step explanation:

Hello!

In this case, since the metal is not given, we can set up the following chemical reactions:

`Be+2HCl\rightarrow BeCl_2+H_2`

Thus, since the HCl is a 2:1 mole ratio with hydrogen, we can use the following setup to calculate the required mass of hydrogen:

`m_(H_2)=42gHCl*(1molHCl)/(36.45gHCl)*(1molH_2)/(2molHCl) *(2.02gH_2)/(1molH_2) \\\\m_(H_2)=1.2gH_2`

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