Question

A complete reaction indicated by the chemical equation below produces 79.0 g of sulfur. Estimate the number of hydrogen atoms found in the amount of water that forms as a second product in this reaction.

2 H2S(g) + SO2(g) → 3 S(s) + 2 H2O(l)

a. 1.98 × 10^24 atoms
b. 4.80 × 10^23 atoms
c. 6.40 × 10^25 atoms
d. 1.02 × 10^26 atoms
e. 3.00 × 10^24 atoms

Answer 1

Answer: A, 1.98x10^24 atoms of H

Explanation: 39.0 g of sulfur = (79.0g/32.1 g/mole) = 2.46 moles S

The balanced equation promises we'll get 2 moles H2O for every 3 moles ofS, a molar ratio of (2 moles H2O)/(3 moles S)

(2.46 moles S)*[(2 moles H2O)/(3 moles S)] = 1.64 moles H2O

(1.64 moles H2O)*(6.02x10^23 molecules H2)/mole H2O)*(2 H atoms/H2O molecule) = 1.97x10^24 atoms of H