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A ball is thrown from an initial height of 3 feet with an initial upward velocity of 36 ft/s. The ball's height h (in feet) after seconds is given by the following.

h=3+36-16
Find all values of t for which the ball's height is 15 feet.

User Dugokontov
by
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2 Answers

7 votes

Final answer:

The ball's height is 15 feet at t = 0.54 s and t = 3.79 s.

Step-by-step explanation:

The equation h = 3 + 36t - 16t² represents the height of the ball in feet after t seconds. To find the values of t for which the ball's height is 15 feet, we can set up the equation:

15 = 3 + 36t - 16t²

This is a quadratic equation. To solve for t, we can rearrange the equation to:

16t² - 36t + 12 = 0

Using the quadratic formula, we find that t = 0.54 s and t = 3.79 s are the values for which the ball's height is 15 feet.

User Quirimmo
by
3.9k points
5 votes

Answer:

t = 0.55 s and t = 1.14 s

Step-by-step explanation:

User Ollie Saunders
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5.3k points