Final answer:
Hershey and Chase's 1952 experiments used radioactive isotopes to label DNA and proteins in bacteriophages, discovering that only the radioactive DNA entered E. coli cells, which led to the conclusion that DNA, not protein, carries the virus' genetic information. Therefore, the correct answer is that radioactive DNA was found in the infected cells, demonstrating DNA carries the virus's genetic material. So the correct answer is d.
Step-by-step explanation:
The Hershey-Chase experiments of 1952 used radioactive isotopes to determine the genetic material in bacteriophages. Radioactive sulfur (35S) was used to label the protein coat since sulfur is present in proteins but not DNA, while radioactive phosphorus (32P) was used to label DNA since phosphorus is a component of DNA and RNA but not typically found in proteins. After allowing the labeled phages to infect E. coli cells, Hershey and Chase used a blender to separate the phage coats from the bacterial cells and then centrifuged the mixture to create a pellet of bacterial cells and a supernatant containing the detached phage coats.
Their results showed that after centrifugation, the 32P was found only in the pellet with the bacterial cells, indicating that DNA is the genetic material that entered the E. coli cells. The 35S was found in the supernatant, which contained the leftover phage parts, meaning that the proteins did not enter the cells and are not the material that carries genetic information. Consequently, option d is correct: Radioactive DNA was found in the infected cells and radioactive protein was found in the medium outside the cells; this demonstrates that DNA carries the virus' genetic information.