Question

Each side of a square is increasing at a rate of 5 cm/s. At what rate (in cm2/s) is the area of the square increasing when the area of the square is 49 cm2

Answer 1

25 cm^2/sec

Explanation:

I my understanding of the question. It doesn't matter what the area of the square is currently is, for example if the area is 25 cm^2, 36 cm^2 or 49cm^2, the rate will ALWAYS increase by rate squared.

rate(a) x rate(b) = rate(area) in this case rate(a) = rate(b)

(5 cm^2/s) (5 cm^2/s) = 25 cm^2/s