Answer:
A) 3783.952 kJ/kg
B) 34.5%
C) 2476.67 kJ/kg
Step-by-step explanation:
A) Determine the rate of heat addition entering the first-stage turbine
Qin ( 1st stage ) = ( h1 - h6 ) + ( h3 - h2 )
= ( 3321.4 - 164.07 ) + ( 3438.566 - 2811.944 )
= 3783.952 kJ/kg
h values are gotten from super heated table
B) Determine the thermal efficiency
n = 34.5%
attached below
C) Rate of heat transfer from working fluid passing through the condenser to the cooling water
Qout = h4 - h5
= 2628.2 - 151.53
= 2476.67 kJ/kg