Question

Given an integer representing a 10-digit phone number, output the area code, prefix, and line number, separated by hyphens.

Ex: If the input is
8005551212,
the output is:
800-555-1212
Hint: Use % to get the desired rightmost digits. Ex: The rightmost 2 digits of 572 are gotten by 572 % 100, which is 72.
Hint: Use // to shift right by the desired amount. Ex: Shifting 572 right by 2 digits is done by 572 // 100, which yields 5. (Recall that integer division discards the fraction).
For simplicity, assume any part starts with a non-zero digit. So 999-011-9999 is not allowed.
LAB: Phone number breakdown 0/100
1 phone_number = int(input)
2
3 num_one = s[:3]
4 num_two = s[3:6]
5 num_three = s[6:]
6
7 final_number = '('+num_one+')'+num_two+'-' +num_three
8 print = final_number

Answer 1

In Python:

phonenum = int(input("10 digit phone number: "))

last4 = phonenum%10000

phonenum//=10000

mid3 = phonenum%1000

phonenum = phonenum//1000

newnum = str(phonenum)+"-"+str(mid3)+"-"+str(last4)

print("New: "+str(newnum))

Step-by-step explanation:

This prompts the user for phone number

phonenum = int(input("10 digit phone number: "))

This gets the last 4 of the phone number using % operator

last4 = phonenum%10000

This shifts the phone number by 4 digit right

phonenum//=10000

This gets the middle 3 of the phone number using % operator

mid3 = phonenum%1000

This shifts the phone number by 3 digit right

phonenum = phonenum//1000

This generates the new phone number which includes the area code...

newnum = str(phonenum)+"-"+str(mid3)+"-"+str(last4)

This prints the formatted phone number

print("New: "+str(newnum))