Question

Lex launched a golfball with his lego catapult. It traveled 7 meters and was in the air for 2 seconds. Please determine the object’s maximum height, horizontal velocity, vertical velocity, actual velocity, and time it reached its maximum height. The angle of release (the catapult’s arm) is 40°.

Horizontal Velocity = vx
Vertical Velocity = V1y
Actual Velocity: V1 = Vactual
Time reached highest point
Height reached!= h
Givens:

dx=

a=

t=


Angle of release:



Table B:
What you need to determine
Formula used
Answer: remember to label the correct units
Distance
Measure it with a meter stick


Time Traveled
Measure it with a stopwatch


Horizontal Velocity




Vertical Velocity




Actual Velocity




Time reached Highest Point




What was the object’s highest point

Answer 1

Step-by-step explanation:

Range R = 7 m

angle of projection θ = 40⁰

u² sin2θ / g = R where u is velocity of throw.

u² sin 80 / g = 7

u² = 69.71

u = 8.35 m/s

horizontal velocity = u cos 40 = 8.35 cos 40

= 6.4 m /s

vertical velocity = u sin 40 = 8.35 sin40

= 5.37 m /s

Maximum height :-

v² = u² - 2gh , u is initial vertical component of throw.

0 = 5.37² - 2 x 9.8 x h

h = 1.47 m

Time to reach max height :--

v = u - gt

o = 5.37 - 9.8 t

t = .55 s