Answer:
0.277
0.723
0.553
Explanation:
Given the data:
Final temp condtn__ below target __above
266K ____________ 13 __________ 40
271 K ____________ 44 __________ 17
274 K ____________ 56 _________ 36
A = final temp ≤ 271K : {44, 40, 13, 17}
Total = {13 + 40 + 44 + 17 + 56 + 36}= 206
B = heat absorbed is above target : {40, 17, 36}
P(AuB) :
AuB = {40, 17} = (40 + 17) = 57
P(AuB} = (AuB) / total = 57 /206 = 0.277
A' = {36, 56,}
B' = {13, 44, 56}
(A'uB') = {36 + 56 + 13 + 44} = 149
P(A'uB') = 149 / 206 = 0.723
P(A) = (44 + 40 + 13 + 17) / 206 = 0.553