Question

What is the equation in slope-intercept form of the line that crosses the x-axis at 36 and is perpendicular to the line represented by y = –49x + 5?

Answer 1

the perpendicular line will have slope = 9/4, the negative inverse of the given line's slope of -4/9. Just change the sign and flip the fraction upside down.

the x intercept of 36 is the point (0,36) plug that point into the point slope formula to get

0 = (9/4)36 + b where b is the y intercept

b=-81

the perpendicular line equation is

y=(9/4)x - 81 in slope intercept form

Answer 2

The equation in slope-intercept form of the line that crossed the x-axis at 36 and is perpendicular to the line represented by y = -4/9x + 5​ is y=9/4x +36

Explanation: