1 Answer

Hate · Answer 1 · 2022-02-26T03:39:02+0000

Answer:

$(f + g)(x) = 3x^{(1)/(3)}+2x^{(1)/(2)}$

$x \ge 0$

Explanation:

Given

$f(x) = 3x^{(1)/(3)}$

$g(x) = 2x^{(1)/(2)}$

Solving (a): (f + g)(x)

In functions:

(f + g)(x) = f(x) + g(x)

So, we have:

$(f + g)(x) = 3x^{(1)/(3)}+2x^{(1)/(2)}$

Solving (b): The domain of f(x)

For (f + g)(x) to be defines, the value of x must be greater than or equal to 0.

Hence, the domain is:

$x \ge 0$

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