Question

If 2y-5x+10=0, find.
(i)y, when x=2
(ii)x, when y=5​

Answer 1

(i) x = 2

Substituting value in the equation,

2y - 5(2) + 10 = 0

2y - 10 + 10 = 0

2y = 0

y = 0

(ii) y = 5

Substituting value in the equation,

2(5) - 5x + 10 = 0

10 - 5x + 10 = 0

20 - 5x = 0

20 = 5x

5x = 20

x = 20/5

x = 4

Answer 2

1. When x = 2, y = 0
2. When y = 5, x = 4

Explanation:

PART I: Value of y, when x = 2

Given information

x = 2

Given expression

2y - 5x + 10 = 0

Substitute values into the expression

2y - 5(2) + 10 = 0

Simplify by multiplication

2y - 10 + 10 = 0

2y = 0

Divide 2 on both sides

2y / 2 = 0 / 2

`\boxed{y=0}`

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PART II: Value of x, when y = 5

Given information

y = 5

Given expression

2y - 5x + 10 = 0

Substitute values into the expression

2(5) - 5x + 10 = 0

Simplify by multiplication

10 - 5x + 10 = 0

20 - 5x = 0

Add 5x on both sides

20 - 5x + 5x = 0 + 5x

20 = 5x

Divide 5 on both sides

20 / 5 = 5x / 5

`\boxed{x=4}`

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