Question

A coach is travelling east wards at 12.6 m/s after 12 second its velocity is 9.5 m/s in the same direction. what is the acceleration and direction of its acceleration?

pls do it with the formula
thx mates :)​

Answer 1

• Initial velocity=u=12.6m/s
• Final velocity=9.5m/s
• Time=t=12s
• Acceleration be a

`\\ \rm\longmapsto a=(v-u)/(t)`

`\\ \rm\longmapsto a=(12.6-9.5)/(12)`

`\\ \rm\longmapsto a=(3.1)/(12)`

`\\ \rm\longmapsto \overrightarrow{a}=0.25m/s^2`