Question

The area of a trapezium is 512 cm², the distance between its parallel sides if the sum of the lengths of the parallel sides is 64 cm is

Answer 1

h = 16 cm

Explanation:

Given that,

The area of a trapezium, A = 512 cm²

The sum of the length of the parallel sides = 64 cm

The area of a trapezium is given by :

`A=(1)/(2)* \text{sum of parallel sides}* height\\\\h=(2A)/(Sum)\\\\=(2* 512)/(64)\\\\=16\ cm`

So, the distance between the parallel sides is 16 cm.