Question

XYZ is a triangle in which XY = 11 centimeters and YZ = 15 centimeters. The length of XZ is in whole centimeters and is greater than 20 centimeters. What are the possible lengths of XZ?

Answer 1

Possible lengths of
`XZ` are
`21\,\,cm,22\,\,cm,23\,\,cm,24\,\,cm,25\,\,cm`

Explanation:

According to triangle inequality theorem,

length of one side is less than the sum of remaining two sides.

Also,

`XY=11\,\,cm\\YZ=15\,\,cm\\XZ>20\,\,cm`

Therefore,

`20<XZ<15+11\\20<XZ<26`

The length of
`XZ` is in whole centimeters.

Therefore, possible lengths of
`XZ` are
`21\,\,cm,22\,\,cm,23\,\,cm,24\,\,cm,25\,\,cm`