Question

Equilibrium constant Kp for the reaction P4(s) + 6Cl2(g) 4PCl3(l) Kp = 1/ P6Cl2 Kp = P4Cl3/ P6P4 Kp = P4Cl3/ (P6P4) (P6Cl2) Kp = 1/ (P6P4) (P6Cl2)

Answer 1

Answer:
`K_p=(1)/([p_(Cl_2)]^6)`

Step-by-step explanation:

Equilibrium constant is defined as the ratio of pressure of products to the pressuure of reactants each raised to the power their stoichiometric ratios. It is expressed as
`K_p`

For the given chemical reaction:

`P_4(s)+6Cl_2(g)\rightarrow 4PCl_3(l)`

The expression for
`K_p` in terms of gaseous is written as:

`K_p=(1)/([p_(Cl_2)]^6)`