Question

A 1 cm2 silicon solar cell has a saturation current of 10A and is illuminated with sunlight yielding a short-circuit photocurrent of 25 mA. Calculate the solar cell efficiency and fill factor.

Answer 1

The answer is "13% and 83%"

Step-by-step explanation:

The highest power is generated for:

`\to (dP)/(dV_a)=0= I_s(e^{(V_m)/(V_t)} -1)-I_(Ph) +(V_m)/(V_t) I_s e^{(V_m)/(V_t)}`

Where voltage,
`V_m`, was its calculated maximum power wattage. This same following transcend national stable coins the power output:

`\to V_m=V_t \ In (1+(I_(ph))/(I_s))/(1+(V_(m))/(V_t))`

The accompanying consecutive values of
`V_m` are done utilizing iteration and an initial value of 0.5 V:

`\to V_m = 0.5,\ 0.542,\ 0.540 \ V`

Efficacy is equivalent to:

`\eta = |(V_(m) I_(m))/(p_(in))| =(0.54 * 0.024)/(0.1)=1.3\%`

Currently,
`I_m` was calculated with the formula of voltage
`V_m` (4.6.1) as well as the sun is presumed to produce
`100 (mW)/(cm^2)` of power.

The fulfillment factor is equal to:

fill factor
`= (V_(m) I_(m))/(V_(oc)I_(sc))= (0.54 * 0.024)/(0.62 * 0.025)=83\%`

where open circuit tension of equations (4.6.1) and I = 0. is calculated. The current is equal to the total current of the photo.