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Given the equation Ca + H2O --> Ca(OH)2 + H2 how many grams of calcium will react completely with 10.0 grams of water? *

User DAiMor
by
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1 Answer

6 votes

Answer: 11.0 g of calcium will react with 10.0 grams of water.

Step-by-step explanation:

To calculate the moles, we use the equation:


\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of
H_2O


\text{Number of moles}=(10.0g)/(18g/mol)=0.55moles

The balanced chemical equation is:


Ca+2H_2O\rightarrow Ca(OH)_2+H_2

According to stoichiometry :

2 moles of
H_2O require = 1 mole of
Ca

Thus 0.55 moles of
H_2O require=
(1)/(2)* 0.55=0.275moles of
Ca

Mass of
Ca=moles* {\text {Molar mass}}=0.275moles* 40g/mol=11g

Thus 11.0 g of calcium will react with 10.0 grams of water.

User Fourat Ben Driaa
by
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