Question

The area of a rectangle is 21 meters squared and the length of the rectangle is 1 meter less than double the width find the dimensions of the rectangle ?

Answer 1

Area = length x width

21 = (2w-1)w

21 = 2w^2 -w

2W^2 - w -21=0

(2w-7 )(W +3)=0
2W-7=0 or w+3=0
W=7/2 or w=-3

Width cannot be negative.
So width is 7/2=3.5
Then the length is 6