Question

What is an equation of the line that passes through the points (−6,−2) and (−3,−3)?

Answer 1

y = -1/3x - 4 (slope-intercept form)

or

x + 3y = -12 (Standard form).

Explanation:

The slope of the line = (-3 - (-2)) / (-3 - (-6))

= -1 / 3.

Using the point-slope form of straight line:

y - y1 = m(x - x1) we have:

y - (-2) = -1/3(x - -6))

y + 2 = -1/3(x + 6

y + 2 = -1/3x - 2

y = -1/3x - 4

In standard form (multiplying thru by 3):

3y = -x - 12

x + 3y = -12.