Answer:
2. The balanced equation is given below
2KClO₃ —> 2KCl + 3O₂
18 moles of oxygen, O₂ were obtained.
3. 21 moles of oxygen, O₂.
Step-by-step explanation:
2. Determination of the number of mole of oxygen produced.
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2KClO₃ —> 2KCl + 3O₂
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂.
Finally, we shall determine the number of mole oxygen, O₂ produced by the reaction of 12 moles of potassium chlorate, KClO₃. This can be obtained as follow:
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂.
Therefore, 12 moles of KClO₃ will decompose to produce = (12 × 3)/2 = 18 moles of O₂.
Thus, 18 moles of oxygen, O₂ were obtained from the reaction
3. Determination of the number of mole of oxygen, O₂ produced by the reaction of 14 moles of KClO₃.
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂.
Therefore, 14 moles of KClO₃ will decompose to produce = (14 × 3)/2 = 21 moles of O₂.
Thus, 21 moles of oxygen, O₂ were obtained from the reaction