Question

For the curve with equation y=x^3-6x^2+20 , find dy/dx

Answer 1

Given:

The equation of a curve is

`y=x^3-6x^2+20`

To find:

The values of
`(dy)/(dx)`.

Solution:

Formulae used:

`(d)/(dx)x^n=nx^(n-1)`

`(d)/(dx)C=0`

We have,

`y=x^3-6x^2+20`

Differentiate with respect to x.

`(dy)/(dx)=3x^(3-1)-6(2x^(2-1))+(0)`

`(dy)/(dx)=3x^(2)-12x^(1)`

Therefore, the value of
`(dy)/(dx)` is
`3x^(2)-12x`.