Question

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100 g of acetic acid (CH, COOH) is dissolved in a 500.0 ml solution. What is the molarity? Report your answer with the
correct number of significant figures

Answer 1

3.34 M

Step-by-step explanation:

Step 1: Given data

• Mass of acetic acid: 100 g

• Volume of solution (V): 500.0 mL (0.5000 L)

Step 2: Calculate the moles of acetic acid

The molar mass of acetic acid is 60.05 g/mol.

100 g × 1 mol/60.05 g = 1.67 mol

Step 3: Calculate the molarity of acetic acid

The molarity is equal to the moles of solute divided by the liters of solution.

M = n/V

M = 1.67 mol/0.5000 L = 3.34 M