Question

Find the absolute maximum and absolute minimum values, if any, of the function. (if an answer does not exist, enter dne. ) f(x) = x2 − x − 5 on [0, 5] absolute maximum absolute minimum.

Answer 1

Explanation:

f(x)=x²-x-5

f'(x)=2x-1

2x-1=0,x=1/2

we find the values of f(x) at x=0,1/2,5

f(0)=0²-0-5=-5

f(1/2)=(1/2)²-1/2-5=0.25-0.5-5=-5.25

f(5)=5²-5-5=25-10=15

absolute minimum=-5.25

absolute maximum=15