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12 votes
12 votes
Find the perimeter of the irregular hexagon with side lengths y, 2y + 11, -3y - 9, y^2, 5y - 1, and бу^2.​

User Yuu Woods
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2 Answers

27 votes
27 votes
y+2y+11+(-3y-9)+y²+(5y-1)+6y²
=y+2y+11-3y-9+y²+5y-1+6y²
=5y+1+7y²

Hope my answer helped u :)
User Aamer Shahzad
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2.8k points
24 votes
24 votes

Answer:

PERIMETER=Y+2Y+11+-3Y-9+Y^2+5Y-1+6Y^2

=7Y^2+4Y+1

User Aldekein
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2.5k points