Answer:
![\boxed {\boxed {\sf 2.62 \ mol \ N_2}}](https://img.qammunity.org/2022/formulas/chemistry/high-school/vwz124dr55c2orrmv7wwugp1r0duvn4na4.png)
Step-by-step explanation:
The relationship between moles and gases is unique. Regardless of the type of gas, there will always be 22.4 liters of gas in 1 mole, as long as it's at STP (standard temperature and pressure).
We can make a ratio using this information.
![\frac {22.4 \ L \ N_2}{ 1 \ mol \ N_2}](https://img.qammunity.org/2022/formulas/chemistry/high-school/q8ct0xhfkw3pmjy45e73ad4db8p8b6wkm3.png)
Multiply by the given number of moles.
![58.6 \ L \ N_2 *\frac {22.4 \ L \ N_2}{ 1 \ mol \ N_2}](https://img.qammunity.org/2022/formulas/chemistry/high-school/5q3io8fhx61rjvl6euo6rjmlvw4mvaqlgz.png)
Flip the fraction so the liters of nitrogen cancel.
![58.6 \ L \ N_2 *\frac {1 \ mol \ N_2}{ 22.4 \ L \ N_2}](https://img.qammunity.org/2022/formulas/chemistry/high-school/iak8h4ne0amvsno57f8gxiqx66ie006k37.png)
![58.6 *\frac {1 \ mol \ N_2}{ 22.4 }](https://img.qammunity.org/2022/formulas/chemistry/high-school/rnyx322sde5p6x1imedb6ojhezht443bjc.png)
![\frac {58.6 \ mol \ N_2}{ 22.4 }= 2.61607143 \ mol \ N_2](https://img.qammunity.org/2022/formulas/chemistry/high-school/i3fvbk9t9lx46sw7tacvpz04sh53pvvjjg.png)
The original measurement of liters has 3 significant figures, so our answer must have the same.
For the number of moles calculated, 3 sig figs is the hundredth place. The 6 in the thousandth place tells us to round the 1 to a 2.
![2.62 \ mol \ N_2](https://img.qammunity.org/2022/formulas/chemistry/high-school/jzfkqfrx18grl2jm3hbn2umsypz9f4w1jp.png)
58.6 liters of N₂ gas at STP is equal to about 2.62 moles.