a=2 b=3 and c=4. then,
a2+2abc+b2+c2
a2+2abc+b2+c2= 2^2+2×2×3×4+3^2+4^2
(replace value of a, b, c by2,3,4 respectively tgen solve)
= 4+48+9+16
= 77………………
Therefore, 77 is correct answer.
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