Question

What is n in the equstion?
n^2+n+2=0

Answer 1

No Solution

Explanation:

The steps are in the (2) pictures below.

Answer 2

✐ Answer:

`n^2+n+2=0\quad :\quad n=-(1)/(2)+i(√(7))/(2),\:n=-(1)/(2)-i(√(7))/(2)`

✍️Steps:--

✰
`n^2+n+2=0`

`n_(1,\:2)=(-1\pm √(1^2-4\cdot \:1\cdot \:2))/(2\cdot \:1)`

`n_(1,\:2)=(-1\pm √(7)i)/(2\cdot \:1)`

`n_1=(-1+√(7)i)/(2\cdot \:1),\:n_2=(-1-√(7)i)/(2\cdot \:1)`

`(-1+√(7)i)/(2\cdot \:1)`

`=(-1+√(7)i)/(2)`

`=-(1)/(2)+(√(7))/(2)`

`(-1-√(7)i)/(2\cdot \:1)`

`=(-1-√(7)i)/(2)`

`=-(1)/(2)-(√(7))/(2)`

`n=-(1)/(2)+i(√(7))/(2),\:n=-(1)/(2)-i(√(7))/(2)`

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hope it helps...

have a great day!!

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