118k views
11 votes
An open pipe on an organ creates

a fundamental frequency at
10500 Hz. How long is the pipe?
(Speed of sound = 343 m/s)
(Unit = m)

An open pipe on an organ creates a fundamental frequency at 10500 Hz. How long is-example-1
User Rubengees
by
5.7k points

1 Answer

6 votes

Answer: 0.0163

Explanation: fn=n x v/2L

Fundamental frequency =f1

1 x (343/2L) = 10500

Rearrange the equation

L= v/(2xFn)

L= 343/(2x10500)

L=0.0163

User Alok C
by
4.4k points