Question

at Niagara Falls, if 505 kg of water fall a distance of 50.0 m, what is the increase in the internal energy of the water at the bottom of the falls? Assume that all of the initial potential energy goes into increasing the water's internal energy and that the final kinetic energy is zero

Answer 1

247702.5 J

Step-by-step explanation:

the question says that all of the initial potential energy is transferred into internal energy, meaning we have to find PEi

PE=mgh

m=505 kg

g=9.81 m/s^2

h=50 m

=>505(9.81)(50)= 247702.5

the internal energy increased by 247702.5 J

Answer 2

Hope that helps

Step-by-step explanation:

the increase in the internal energy of the water at the bottom of the falls

= mgh

= 505 * 9.81 * 50

= 247703 J ----answer