Question

Solve the equation by completing the square. 0=x^2-14x+46 A. B. C. D.

Answer 1

x1=7-(square)3 x2=7+(square)3

Explanation:

Swipe the sides of equation

Solve the quadratic equation ax^2+bx+c=0

Then using: x=((-)b+-(square)b^2-4ac):2a

Separate the solutions

Simplify

Answer 2

x = 16

Explanation:

0=x^2-14x+46 is to be solved for x by completing the square. The first two terms, x^2 and -14x, are the incomplete square. We must find a term to add to, and then subtract from x^2 - 14x, so that we have a perfects square on the left and a negative number on the right:

x^2 - 14x = x^2 - 14x + (half of -14)^2 - (half of -14)^2 results in transformation of the original 0=x^2-14x+46 to

x^2 - 14x + 49 - 49 + 46 = 0, which simplifies to:

(x - 7)^2 - 3 = 0. We want to solve this for x.

To do that, rewrite (x - 7)^2 - 3 = 0 as (x - 7)^2 = 3, and then square both sides. We get:

x - 7 = 9, or x = 16