Question

Find the equation of a line that passes through the point (-2,4) and has a gradient of -3.

Leave your answer in the form
y
=
m
x
+
c

Answer 1

Equation of a line is y = mx +c

m is the gradient, which is given as -3 so now you have:

y = -3x + c

Replace y and x with the given point and solve for c:

4 = -3(-2) + c

Simplify:

4 = 6 + c

Subtract 6 from both sides:

c = -2

The equation becomes:

y = -3x-2