Answer:
There is no value of x to fit this requirement.
Explanation:
The 2 perimeters in terms of x are:
4(x + 3) for the square and
2(x+1) + 2(x +4) for the rectangle
and these need to be equal so
we equate these 2 and solve for x:
4(x + 3) = 2(x+1) + 2(x +4)
4x + 12 = 2x + 2 + 2x + 8
4x + 12 = 4x + 10
4x - 4x = 10 - 12
0 = -2 which is of course absurd so there is no solution to this equation.