Question

In ΔMNO, the measure of ∠O=90°, the measure of ∠M=11°, and NO = 80 feet. Find the length of OM to the nearest tenth of a foot. Please show work.

Answer 1

OM = 411.56 ft

Explanation:

tan 11 = 80/x

0.1944 = 80/x

x = 411.56 ft